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Bullet having a mass of 10 gram and moving with a speed of 1.5 metre per second penetrates a thick wooden plank of mass 900 gram the plank was initially at rest the bullet gets embedded in the plank both andmove together determine their velocity.

Asked by Umeshkhewalkar02 5th July 2019, 9:43 AM
Answered by Expert
Answer:
let m be mass of bullet and M be mass of wooden plank
let u be initial velocity of bullet and v be the velocity after bullet is embedded on wooden plank
 
initial momentum :-  m×u + M×0 = 10×10-3 × 1.5 = 15×10-3  kg-m/s
Final momentum :- ( m + M )×v = 910×10-3× v   kg-m/s
 
By conservation of momentum :  910×10-3 × v = 15×10-3
 
Hence ,  v = 15/910 ≈ 0.0165 m/s = 1.65 cm/s
Answered by Expert 5th July 2019, 10:08 AM
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