Maharashtra Class 9 Answered
Bullet having a mass of 10 gram and moving with a speed of 1.5 metre per second penetrates a thick wooden plank of mass 900 gram the plank was initially at rest the bullet gets embedded in the plank both andmove together determine their velocity.
Asked by Umeshkhewalkar02 | 05 Jul, 2019, 09:43: AM
Expert Answer
let m be mass of bullet and M be mass of wooden plank
let u be initial velocity of bullet and v be the velocity after bullet is embedded on wooden plank
initial momentum :- m×u + M×0 = 10×10-3 × 1.5 = 15×10-3 kg-m/s
Final momentum :- ( m + M )×v = 910×10-3× v kg-m/s
By conservation of momentum : 910×10-3 × v = 15×10-3
Hence , v = 15/910 ≈ 0.0165 m/s = 1.65 cm/s
Answered by Thiyagarajan K | 05 Jul, 2019, 10:08: AM
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