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Bar mangnet bent into a semicircle

Asked by 3rd September 2008, 4:03 PM
Answered by Expert
Answer:

 

Let

L-  be the length of the bar magnet which now is bent into a semi circle.

m- pole strength

M- original magnetic moment
M' - the new magnetic moment

r - radius of the semicircle that has been made.

M = m x L

The distance between the poles now becomes 2r from L(earlier) .
Also L= r (beacuse the length is now the circumference of the semi circle)
That gives r = L/

Hence, M' = m x 2 r = mx 2 (L / ) = (2/) M

 

Answered by Expert 20th October 2008, 2:56 AM
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