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CBSE Class 11-commerce Answered

(b²-c²) cotA + (c²-a²) cotB + (a²+b²) cotC =0

Asked by Harshashok2002 | 30 Jul, 2017, 08:47: AM

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begin mathsize 16px style Consider space only space first space term open parentheses straight b squared minus straight c squared close parentheses cotA equals open parentheses straight b squared minus straight c squared close parentheses fraction numerator cosA over denominator sin straight A end fraction equals fraction numerator open parentheses straight b squared minus straight c squared close parentheses over denominator sinA end fraction cross times fraction numerator straight b squared plus straight c squared minus straight a squared over denominator 2 bc end fraction equals fraction numerator open parentheses straight b squared minus straight c squared close parentheses over denominator ka end fraction cross times fraction numerator straight b squared plus straight c squared minus straight a squared over denominator 2 bc end fraction Similarly space you space can space do space it space for space the space next space two space terms and space on space simplifying space you space will space get space RHS space as space 0. end style

Answered by Sneha shidid | 31 Jul, 2017, 09:23: AM

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CBSE 11-commerce - Maths

<div>(b²-c²) cotA + (c²-a²) cotB + (a²+b²) cotC =0</div>

Asked by Harshashok2002 | 30 Jul, 2017, 08:47: AM

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