(ax+b)/(cx+d)<0 Plz. explain process
Asked by Sourav Sett
8th September 2013,
5:06 PM
Answered by Expert
Answer:
Fraction is negative in two cases:
- Numerator is negative, denominator is positive: {ax+b<0, cx+d>0. This gives x<-b/a and x>-c/d
- Numerator is positive, denominator is negative: {ax+b>0, cx+d<0. This gives x>-b/a and x<-c/d
Answered by Expert
8th September 2013,
10:22 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
Free related questions
20th April 2017,
8:17 AM
- sin
26th April 2017,
8:00 AM
4th May 2017,
10:08 AM
4th May 2017,
9:30 AM
4th May 2017,
9:59 AM
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Sets
- 2 Relations and Functions
- 3 Principle of Mathematical Induction
- 4 Binomial Theorem
- 5 Sequences and Series
- 6 Straight Lines
- 7 Conic Sections
- 8 Introduction to Three Dimensional Geometry
- 9 Limits and Derivatives
- 10 Mathematical Reasoning
- 11 Statistics
- 12 Probability
- 13 Trigonometric Functions
- 14 Complex Numbers and Quadratic Equations
- 15 Permutations and Combinations
- 16 Linear Inequalities
Trending Tags
Latest Questions
ICSE IX Mathematics
Asked by sonukushgzp
19th August 2019,
11:12 AM
ICSE IX Geography
Asked by Runu_7
19th August 2019,
6:46 AM
ICSE IX History and Civics
Asked by Runu_7
19th August 2019,
6:43 AM
