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Home / Doubts and Solutions/CBSE/Class 11 Science/Mathematics

(ax+b)/(cx+d)<0 Plz. explain process

Asked by Sourav Sett 8th September 2013, 5:06 PM
Answered by Expert
Answer:

Fraction is negative in two cases:

  1. Numerator is negative, denominator is positive: {ax+b<0, cx+d>0. This gives x<-b/a and x>-c/d
  2. Numerator is positive, denominator is negative: {ax+b>0, cx+d<0. This gives x>-b/a and x<-c/d
Answered by Expert 8th September 2013, 10:22 PM
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