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CBSE Class 11-science Answered

At 298 K, the percentage ionization in a 0.16 molar solution of CH3NH2 is 4.7%. Calculate the pH of a 0.160-molar solution of CH3NH2 at 298 K                             CH3NH2 + H2O begin mathsize 11px style rightwards harpoon over leftwards harpoon end style CH3NH3+ + OH¯
Asked by Topperlearning User | 04 May, 2015, 02:10: PM
answered-by-expert Expert Answer
Cα = (0.160) (0.047) = 7.5 x 10-3M
[H3O+] = (1.0 x 10-14 / 7.5 x 10-3) = 1.3 x 10-12 M

pH = - log[H3O+] = 11.89

Answered by | 04 May, 2015, 04:10: PM
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