CBSE Class 11-science Answered
At 298 K, the percentage ionization in a 0.16 molar solution of CH3NH2 is 4.7%. Calculate the pH of a 0.160-molar solution of CH3NH2 at 298 K CH3NH2 + H2O CH3NH3+ + OH¯
Asked by Topperlearning User | 04 May, 2015, 02:10: PM
Expert Answer
Cα = (0.160) (0.047) = 7.5 x 10-3M
[H3O+] = (1.0 x 10-14 / 7.5 x 10-3) = 1.3 x 10-12 M
pH = - log[H3O+] = 11.89
Answered by | 04 May, 2015, 04:10: PM
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