Assume that the thermal conductivity of copper is four times that of brass. Two rods of copper and brass, of the same length and cross section are joined end to end. The free end of the copper rod is kept it 0 °C and the free end of the brass rod at 100 °C. Calculate the temperature at the junction of the two rods at equilibrium. Ignore radiation losses.
Let the thermal conductivity of brass be K.
Hence, thermal conductivity of copper = 4 K
Length of each rod = x
Suppose θ is the temperature of the junction of the two rods in equilibrium.
Rate of flow of heat energy through brass = rate of flow of heat energy through copper
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