Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

As one moves to a place 3200 Km above the earth's surface, the acceleration due to gravity reduces to 4/9 of its value at the earth's surface. Calculate the radius of the earth from this data?

Asked by rajneesh kumar 13th September 2013, 11:09 AM
Answered by Expert
Answer:
height above earth's surface, h = 3200 km
let radius of earth = R
thus according to the following expression for acceleration due to gravity.
g = GM/R2 at the surface of earth    -1
at height h, distance between this point and the center of earth, H = 3200 + R
4g/9 = GM/H2                               -2
thus dividing equation 1 and 2
 
4/9 = (R/H)2
or 4/9 = (R/(3200 + R))2
 
this can be solved easily to calculate R
Answered by Expert 13th September 2013, 11:31 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer 8/10

Your answer has been posted successfully!

Latest Questions

CBSE VIII GK
Asked by Rajendersansanwal88581 23rd April 2019, 5:41 AM
Meghalaya IX History
Asked by carlvincent 23rd April 2019, 3:25 AM
CBSE XII Science Physics
qsnImg
Asked by jain.pradeep 23rd April 2019, 2:09 AM

Chat with us on WhatsApp