CBSE Class 10 Answered
As observed from the top
of a lighthouse, 100 metres high above sea level, the angle of depression of
a ship moving directly towards it, changes from 30o to 60o.
Determine the distance travelled by the ship during the period of
observation.
Asked by Topperlearning User | 27 Jul, 2017, 11:02: AM
Expert Answer
Let A and B be the two positions of the ship. Let d be the distance travelled by the ship during the period of observation, i.e., AB=d metres.
Suppose that the observer is at the point P. It is given that PC = 100m.
Let h be the distance (in metres) from B to C.
In right triangle PCA,
= cot30o =
d+h = 100 ... (i)
In triangle PCB,
= cot60o =
h = metres
Putting the value of h in (i), we get,
d= 100(approx.)
Thus, the distance travelled by the ship from A to B is 115.47 metres (approx.).
Answered by | 27 Jul, 2017, 01:02: PM
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