Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Arrange cyclohexane, KCL, CH3OH, CH3CN in order of their increasing solubility in n octane.

 

Asked by j4jaigupta1998 | 09 Jun, 2015, 10:00: AM
answered-by-expert Expert Answer

The solubility of a non-polar solute is more than that of a polar solute in the n-octane. n-octane is a non-polar solvent.

Cyclohexane  : non-polar

KCl                : ionic

CH3OH           : polar covalent

CH3CN           : weakly polar covalent

The order of increasing polarity is:

Cyclohexane < CH3CN <  CH3OH < KCl

Reason:

Cyclohexane and n-Octane are non polar solvents and hence mix with each other in all proportions.

KCl is an ionic compound and n-octane is non polar, therefore do not dissolve in n-octane.

Methyl alcohol and methyl cyanide both are polar compounds, but methyl alcohol is more polar, and methyl cyanide is less polar. So methyl cyanide will dissolve more in n-octane .

Therefore, the order of increasing solubility is:

KCl < CH3OH < CH3CN < Cyclohexane

Answered by Hanisha Vyas | 10 Jun, 2015, 10:42: AM
CBSE 12-science - Chemistry
Asked by sameerteli003 | 08 Apr, 2024, 11:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by rashmij34 | 27 Feb, 2024, 04:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by sagarmishra | 27 Feb, 2024, 04:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by kalandi.charan.407 | 08 Feb, 2024, 01:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by premkhare2006 | 24 Jan, 2024, 09:50: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by saritanohar22 | 13 Jan, 2024, 01:25: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×