CBSE Class 10 Answered
Arithmetic Progression
Asked by | 26 Feb, 2009, 04:35: PM
Expert Answer
Let the first term be a and the common difference be d.
Remember that two find two unknown quantities, we must have two equations involving them, which we'll solve and get the answer.
the first seven terms are
a,a+d, a+2d...a+6d
So their sum= (7/2)[a+a+6d]=(7/2)[2a+6d]
So,
according to question
(7/2)[2a+6d]=20
This gives us
7a+21d=20...(i)
The next seven terms are
a+7d,a+8d,...a+13d
these terms can be thought of as in A.P. with first terms as a+7d and common difference as d.
So their sum = (7/2)[a+7d+a+13d]=17
This gives us
7a+70d=17..(ii)
Solving the two equations we get
the values of a and d.
Answered by | 27 Feb, 2009, 03:00: PM
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