CBSE Class 10 Answered
A.P.
Asked by khushal305 | 03 Sep, 2009, 04:30: PM
Expert Answer
Sm = m(2a+(m-1)d)/2 = n
2a+(m-1)d = 2n/m........(1)
Sn = n(2a+(n-1)d)/2 = m
2a+(n-1)d = 2m/n.........(2)
(1) - (2) gives,
(m-1)d - (n-1)d = 2n/m - 2m/n
(m-n)d = 2(n2-m2)/mn
d = -2(m+n)/mn
Sm+n = (m+n)(2a+(m+n-1)d)/2
= m(a+(m+n-1)d)/2 + n(a+(m+n-1)d)/2
= n + mnd/2 + m + mnd/2
= n + mnd + m
= (m+n) + mn(-2(m+n)/mn) ............................substituting the value d.
= -(m+n)
Regards,
Team,
TopperLearning.
Answered by | 03 Sep, 2009, 11:37: PM
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