CBSE Class 9 Answered
AOB is a diameter of the circle and C, D, E
are any three points on the semicircle. Find the value of ACD + BED.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Join BC.
Then ACB = 90o [Angle in a semi circle]
Since DCBE is a cyclic quad.
BCD + BED = 180o
Adding ACB on both sides
BCD + BED + ACB = ACB + 180o.
(BCD + ACB) + BED = 90o + 180o
ACD + BED = 270o
Answered by | 04 Jun, 2014, 03:23: PM
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