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CBSE Class 9 Answered

AOB is a diameter of the circle and C, D, E are any three points on the semicircle. Find the value of ACD + BED.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

Join BC.

Then ACB = 90o [Angle in a semi circle]

Since DCBE is a cyclic quad.

BCD + BED = 180o

Adding ACB on both sides

BCD + BED + ACB = ACB + 180o.

(BCD + ACB) + BED = 90o + 180o

ACD + BED = 270o

Answered by | 04 Jun, 2014, 03:23: PM
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