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# ⭕ Answer in detail... Thanks

Asked by jhajuhi19 23rd November 2020, 2:20 AM
At position A , observed frequencies  of sound from both sources of sound  is given as

fS1 = fS2 = [ 1 + (vo / v ) ] fs

where vo is velocity of observer,  v is speed of sound and fs is the actual frequency of sources S1 and S2 .

(Observer is moving towards both sources )

Since both observed frequencies are same beats will not be heard.

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At position B , observed frequency  of sound from source-1   is given as

fS1 =  [ 1 - (vo / v ) ] fs

(Observer is moving away from Source S1 )

At position B , observed frequency  of sound from source-2   is given as

fS2 =  [ 1 + (vo / v ) ] fs

(Observer is moving towards Source S2 )

Since  observed frequencies are slightly different  ( fs2 > fs1 ) , beats will be heard.

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At position C , observed frequencies  of sound from both sources of sound  is given as

fS1 = fS2 = [ 1 - (vo / v ) ] fs

(Observer is moving away from both sources )
Since both observed frequencies are same beats will not be heard.

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Answer to the question :-  (3) Beats will not be heard at A and C , but will be heard at B
Answered by Expert 23rd November 2020, 9:47 AM
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