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Home / Doubts and Solutions/NEET/Physics

⭕ Answer in detail... Thanks

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Asked by jhajuhi19 23rd November 2020, 2:20 AM
Answered by Expert
Answer:
At position A , observed frequencies  of sound from both sources of sound  is given as
 
fS1 = fS2 = [ 1 + (vo / v ) ] fs 
 
where vo is velocity of observer,  v is speed of sound and fs is the actual frequency of sources S1 and S2 .
 
(Observer is moving towards both sources )
 
Since both observed frequencies are same beats will not be heard.
 
----------------------------------------------
 
At position B , observed frequency  of sound from source-1   is given as
 
fS1 =  [ 1 - (vo / v ) ] fs 
 
(Observer is moving away from Source S1 )
 
At position B , observed frequency  of sound from source-2   is given as
 
fS2 =  [ 1 + (vo / v ) ] fs 
 
(Observer is moving towards Source S2 )
 
Since  observed frequencies are slightly different  ( fs2 > fs1 ) , beats will be heard.
 
--------------------------------------------------
 
At position C , observed frequencies  of sound from both sources of sound  is given as
 
fS1 = fS2 = [ 1 - (vo / v ) ] fs 
 
(Observer is moving away from both sources )
 Since both observed frequencies are same beats will not be heard.
 
---------------------------------------------------
 
Answer to the question :-  (3) Beats will not be heard at A and C , but will be heard at B
Answered by Expert 23rd November 2020, 9:47 AM
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