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angular momentum

Asked by sachinkandel 20th April 2019, 8:18 PM
Answered by Expert
Angular momentum is the rotational analogue of linear momentum. Like moment of a force, angular momentum
is also a vector product. It could also be referred to as moment of (linear) momentum.  

Consider a particle of mass m and linear momentum p at a position r relative to the origin O.
The angular momentum l of the particle with respect to the origin O is defined to be
l = r × p
The magnitude of the angular momentum vector is  l = r p sinθ

where p is the magnitude of p and θ is the angle between r and p. We may write l = r p⊥ = rp
where r(= r sinθ) is the perpendicular distance of the directional line of p from the origin and
p(= p sinθ ) is the component of p in a direction perpendicular to r.
Angular momentum is zero (l = 0), if the linear momentum vanishes (p = 0), or if the particle is at
the origin (r = 0), or if the directional line of p is parallel to direction of r ( θ = 0° or 180°).
Answered by Expert 20th April 2019, 10:48 PM
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