CBSE Class 11-science Answered
And aeroplane is flying horizontally at an altitude of 1 km with a velocity of 200 km/h it drops a little packet man to land on a ship moving in the same direction with a velocity of 20 km per our show that the package should be dropped when the horizontal distance between the plane in shape is 715 m solve the problem for the keys when ship is moving in opposite direction
Asked by nilaydeshpande773 | 19 Aug, 2019, 08:14: PM
Expert Answer
As shown in figure. Let airplane fly 200 km/hr at a height of 1 km above water surface when it drops the package.
speed of air plane = 200 km/hr = 200×(5/18) m/s ≈ 55.56 m/s
if flying air plane drops the package,
then initial horizontal velocity of package = 55.56 m/s
but velocity in vertical direction is zero.
Hence H = (1/2)g t2 or 1000 =(1/2)×9.8×t2 ...............(1)
Hence time to reach the deck of ship = (1000/4.9)1/2 ≈ 14.3 s
Horizontal distance S travelled by package = Horizontal velocoty×time = 55.56×14.3 ≈ 794 m
speed of ship = 20 km/hr = 20×(5/18) ≈ 5.56 m/s
Since ship also moving in the direction of movement of airplane,
required distance between airplane and ship at the time of dropping the package is [ 794 - (5.56×14.3) ] ≈ 715 m
If the ship is moving in opposite direction, then required distance between airplane and ship
at the time of dropping the package is [ 794 + (5.56×14.3) ] ≈ 874 m
Answered by Thiyagarajan K | 19 Aug, 2019, 10:04: PM
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