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An urn contains 25 balls of which 10 balls bear a mark X and the remaining 15 bear a mark Y. A ball is drawn at random from the urn, its mark is noted down and it is replaced. If 6 balls are drawn in this way, find the probability that (i) all will bear X mark.

Asked by prabhakar p 14th March 2013, 8:31 AM
Answered by Expert
Answer:
It depends on how you have defined Z. If Z has been defined as the number of times a ball with mark X has been drawn, then yeah, it should be Z = 6. However, if it has been defined as the number of times a ball with mark Y is drawn, then it should be Z = 0 as we are drawing all the balls with mark X on them.   
Answered by Expert 14th March 2013, 9:47 PM
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