Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

An unknown metal of mass 192 g heated to a temperature of 100ºC was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4ºC Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5ºC (Specific heat of brass is 394 J kg–1 K–1) (1) 1232 J kg–1 K–1 (2) 458 J kg–1 K–1 (3) 654 J kg–1 K–1 (4) 916 J kg–1 K–1
Asked by swathibinoj | 02 Apr, 2019, 08:37: PM
answered-by-expert Expert Answer
Water equivalent = (0.128×394)/4200 = 12.00gms
Mw × Sw = Mmet × Smet
Mw  = (Mmet × Smet)/Sw
Total water = 240 + 12 = 252 gm
Hence,
Heat lost by metal= 192 × Sm × (100 – 21.5) = 15072
Heat gained by warter= 252 × 4200 × (21.5 – 8.4) = 13865040
So Sm = 916 J/kgK
 
 
Answered by Ankit K | 02 Apr, 2019, 10:07: PM
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rosysahu678 | 02 Mar, 2024, 06:09: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vaddevenkatesulu56 | 26 Feb, 2024, 09:02: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rustampathan | 25 Feb, 2024, 06:39: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
ans
question image
Asked by hjha9709 | 25 Feb, 2024, 12:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×