CBSE Class 11-science Answered
An unknown metal of mass 192 g heated to a temperature of 100ºC was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4ºC Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5ºC (Specific heat of brass is 394 J kg–1 K–1) (1) 1232 J kg–1 K–1 (2) 458 J kg–1 K–1 (3) 654 J kg–1 K–1 (4) 916 J kg–1 K–1
Asked by swathibinoj | 02 Apr, 2019, 08:37: PM
Expert Answer
Water equivalent = (0.128×394)/4200 = 12.00gms
Mw × Sw = Mmet × Smet
Mw = (Mmet × Smet)/Sw
Total water = 240 + 12 = 252 gm
Hence,
Heat lost by metal= 192 × Sm × (100 – 21.5) = 15072
Heat gained by warter= 252 × 4200 × (21.5 – 8.4) = 13865040
So Sm = 916 J/kgK
Answered by Ankit K | 02 Apr, 2019, 10:07: PM
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