CBSE Class 10 Answered
AN OBJECT MOVES WITH ACCELERATION "ALPHA" FOR SOME TIME AND "BETA"FOR ANOTHER TIME.THE OBJECT STARTS FROM REST AND IN ANOTHER HALF FINALLY COMES TO REST .THE EVENT TAKES PLACE IN TIME "t".FIND THE MAXIMUM VELOCITH ATTAIED AND TOTAL DISTANCE TRAVELLED BY THE OBJECT?
Asked by ENGLISH DSOUZA | 04 Jun, 2014, 06:12: AM
Expert Answer
The question is not formulated properly:- First I formulate the question
Question:-
An oobject strats from rest and moves with acceleration α for time t1. Then the particle moves with acceleration β for time t2. Then finally the particle comes to rest in time t3. Find the maximum speed and the total distance travelled.
Answer:-
For duration t1 :- distance travelled S1 = and final velocity v1 = α t1
For duration t2:- distance travelled S2 = and final velocity v2 =
for duration t3 :- retardation = and distance travelled S3 =
total distance travelled = S1+S2+S3; maximum speed =
Answered by | 05 Jan, 2018, 05:27: PM
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