Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

an iron rod 4m long and 0.5cm2 in cross section stretches 1mm when a mass of 225kg is hung from its lower end . calculate youngs modolus of iron?
 
Asked by sammy123 | 19 Mar, 2015, 06:42: PM
answered-by-expert Expert Answer
begin mathsize 12px style Young apostrophe straight s space modolus comma space straight Y space equals bevelled fraction numerator space open parentheses straight F over straight A close parentheses over denominator open parentheses begin display style fraction numerator increment straight L over denominator straight L end fraction end style close parentheses end fraction open parentheses fraction numerator increment straight L over denominator straight L end fraction close parentheses space equals space fraction numerator 1 space cross times space 10 to the power of negative 3 end exponent space straight m over denominator 4 space straight m end fraction space equals space 0.25 space cross times space 10 to the power of negative 3 end exponent space straight m straight F space equals space 225 space kg space cross times space 9.8 space straight m divided by straight s squared space equals space 2205 space straight N Given space that space straight m space equals space 0.5 space cross times space 10 to the power of negative 4 end exponent space straight m squared Substituting space the space values space we space get colon straight Y space equals space bevelled fraction numerator space open parentheses fraction numerator space 2205 over denominator 0.5 space cross times space 10 to the power of negative 4 end exponent space straight m squared end fraction close parentheses over denominator open parentheses begin display style 0.25 space cross times space 10 to the power of negative 3 end exponent space straight m end style close parentheses end fraction space space space equals 1.76 space cross times 10 to the power of 11 space straight N divided by straight m squared end style
Answered by Yashvanti Jain | 11 Dec, 2017, 07:23: PM

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 11-science - Physics
Shear strength of steel is 80 GPa. Force required to punch a square hole of side 1 cm in 5 mm thick steel sheet is X MN. Find the value of x
Asked by bhavanamajeti999 | 18 Dec, 2023, 03:33: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
define hokes law
Asked by ankitkg62880 | 04 Mar, 2022, 10:05: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
10. Sudden cooling is known as
Asked by radhakrishna200329 | 15 Feb, 2022, 09:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Que:- which are the top 5 elastic substances in the world?
Asked by advssdrall | 10 Nov, 2021, 09:01: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
 Calculate the change in volume of an iron block 10 cm × 20 cm × 5 cm if its temperature is raised from 10 °C to 40 °C. Given, coefficient of linear expansion of iron =1.2 × 10-5 °C  
Asked by medhavi1615 | 21 May, 2021, 11:32: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
What is hooks law of physics?    
Asked by kushalnadiad | 23 Oct, 2019, 08:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
What is a perfectly plastic body?
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
What do you mean by the elastic limit?
Asked by Topperlearning User | 24 Jul, 2014, 03:25: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
What is elastic fatigue?
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
What do you mean by stress?  Is it scalar or vector?
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×