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An engineer works in a factory out of station. A car is sent for him from the factory every day. The car arrives at the station exactly at the same time as the train. One day the man arrives one hour before his usual time. Without waiting for the car, he starts walking towards the factory. On the way, he meets the car. The man reaches the factory 10 minutes before the usual time. Find out the time for which the man keeps walking  
Asked by utkarsh1543 | 19 Apr, 2019, 10:08: AM
answered-by-expert Expert Answer
The time duration for which the engineer walk before he met the car is time reached before-half the time he saved as the car is travelling a two way journey. 60-5=55 mins
Car saved total time in forward and backward path since the car saved total 10 minutes then it will contain both 5 minutes of forward and 5 minutes of backward motion. But for the person the time he is save for just the backward motion of car.
Answered by Ankit K | 20 Apr, 2019, 09:06: AM

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