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An engine is hauling a train of mass M kg a level track at a constant speed v m/s. The resistance due to friction is f N/kg. What extra power must the engine develop to maintain the speed up a gradient of h in s:

Asked by Arushi Juyal 12th November 2017, 3:00 PM
Answered by Expert
Power = force × speed
additional resistive force due to friction = f × M
Hence additional power is f × M × v
Answered by Expert 13th November 2017, 3:22 PM
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