CBSE Class 12-science Answered
An element has a body centered cubic structure with a cell edge of 288 pm. The density of the elements is 7.2 gcm-3. Calculate the number of atoms present is 208 g of the element.
Asked by Topperlearning User | 17 Jun, 2016, 09:53: AM
Expert Answer
Volume of unit cell = (288 pm)3 = (288 
10-10 cm)3
= 2.389 10-23 cm3
Volume of 208 g of the element = 
Number of unit cells = 
= 12.09 1023
For a b. c. c. structure, number of atoms per unit cell = 2
Number of atoms present in 208 g
=No. of atoms per unit cell No. of unit cells
= 2 12.09 1023 = 24.18 1023 = 2.418 1024.
Answered by | 17 Jun, 2016, 11:53: AM
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