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CBSE Class 12-science Answered

An electron of energy 200 eV describes circle in a magnetic field of 0.2T. Calculate the radius of the circle. Given mass of electron is 9 x 10-31 kg, 1 eV=1.6 x 10-19 J.
Asked by Topperlearning User | 20 May, 2015, 10:19: AM
answered-by-expert Expert Answer

Given:

E= 200eV= 200 x 1.6 x 10-19 J

B= 0.2T

q= 1.6 x 10-19C

m=  9 x 10-31 kg

Kinetic energy of particle is given as:

Syntax error from line 1 column 49 to line 1 column 90. Unexpected 'mathvariant'.

 

Answered by | 20 May, 2015, 12:19: PM

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