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an electron moving at speed of 5x10^4 m/sec enters into uniform electric field and gets an accelaration of 104 m/sec square in the direction of its intial motion cal the time it will take double its speed  & cal the distance travelled to this journey.

Asked by Giriraj 3rd May 2015, 11:02 PM
Answered by Expert
Answer:

Hi Giriraj Sharma,

begin mathsize 12px style Given colon straight u space equals space 5 space cross times space 10 to the power of 4 space straight m divided by straight s straight a space equals space 10 to the power of 4 space straight m divided by straight s squared From space kinematic space eqution space of space motion comma straight v space equals space straight u space plus space at From space the space given space condition comma space when space speed space becomes space double space we space have comma 2 straight u space equals space straight u space plus at straight u space equals space at straight t space equals space straight u over straight a space equals space fraction numerator 5 space cross times space 10 to the power of 4 space over denominator 10 to the power of 4 end fraction space equals space 5 space straight s To space calulate space total space distance comma straight S space equals space ut space plus space 1 divided by 2 space at squared straight S space equals space space 5 space cross times space 10 to the power of 4 space space cross times space 5 space plus space 1 half space cross times space 10 to the power of 4 space cross times space 5 squared straight S space equals space 25 space cross times space 10 to the power of 4 space plus space 12.5 space cross times space 10 to the power of 4 straight S space equals space 37.5 space cross times space 10 to the power of 4 space straight m end style

Answered by Expert 4th May 2015, 6:18 PM
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