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an ecess of AgNO3 is added to 100 ml of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. the number of mole of AgCl precipited would be

Asked by nitinkawadkar | 26 Apr, 2019, 07:15: AM

Expert Answer

Given:

Molarity of solution of dichlorotetraaquachromium (III) chloride = 0.01 M

Volume of solution of dichlorotetraaquachromium (III) chloride = 100 ml

The formula of dichlorotetraaquachromium (III) chloride is [Cr(H₂O)Cl₂]Cl

On ionisation,

space space space space space space space space space space space space space space space space left square bracket Cr left parenthesis straight H subscript 2 straight O right parenthesis Cl subscript 2 right square bracket Cl space space rightwards arrow with blank on top space space left square bracket Cr left parenthesis straight H subscript 2 straight O right parenthesis Cl subscript 2 right square bracket to the power of plus space space space plus space space space Cl to the power of minus space Initial space space space space space space space space space space 100 space cross times 0.01 space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space 0 Final space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space 1 space space mol space space space space space space space space space space space space space space space 1 space mol So space 1 space mol space of space Cl to the power of minus space ions space will space react space with space 1 space mol space of space AgNO subscript 3 space mole space of space space left square bracket Cr left parenthesis straight H subscript 2 straight O right parenthesis Cl subscript 2 right square bracket Cl space 0.1 space straight M space 100 space ml space solution space is comma No. space of space moles space equals space Molarity space cross times Volume space space space space space space space space space space space space space space space space space space space space space equals space 0.01 space cross times 0.1 space space space space space space space space space space space space space space space space space space space space space space equals space 0.001 space mol Hence comma space 0.001 space mol space of space Cl to the power of minus space ions space will space react space with space 0.001 space mole space of space AgNO subscript 3 So space number space of space moles space of space AgCl space formed space is space 0.001 space mol.

Moles of AgCl formed is 0.001 mol

Answered by Varsha | 26 Apr, 2019, 12:13: PM

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