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an average induced emf of .4v appears in a coil when the current in it is changed from 10A in one direction to 10 A inthe opp direction in .40 sec find the coeff of self inductance of the coil

Asked by JOTIN RAJ RAJ 25th February 2013, 8:54 AM
Answered by Expert
Answer:
emf induced=?=L di/dt
0.4=L20/0.4
L=0.008 H
Answered by Expert 25th February 2013, 3:38 PM
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