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algebra

Asked by 12th February 2009, 8:57 PM
Answered by Expert
Answer:

for equal roots of Ax2 + Bx + C = 0 we have  B2 = 4AC

so from above eqn  (2mc) 2 = 4  (1+m)2  (c2-a2)   ====>  4 m2 c2 = 4 ( c2-a2 + m2 c2-a2 m2 )

solving we get  c2=a2(1+m2)

Answered by Expert 13th February 2009, 12:51 AM
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