CBSE Class 10 Answered
algebra
Asked by suchet_r | 31 Aug, 2009, 07:03: PM
Expert Answer
Let the number of pottery articles in a day be n, and cost of production of each be p rupees.
2n +3 = p
np = 90
p = 90/n
2n + 3 = 90/n
2n2 + 3n - 90 = 0
n = [-3 ±(9 - (4)(2)(-90))]/4
n = [-3 ±(729)]/4
n = [-3 +27]/4
n = 6 and p = 90/6 = 15.
Number of articles produced = 6,
Cost of each article = 15.
Regards,
Team,
TopperLearning.
Answered by | 31 Aug, 2009, 11:03: PM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT