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  Ag is movalent with atomic mass 108 Cu is divalent with atomic mass 63.6. The same electric current is passed for the same length of time through a Ag coulometer and a Cu coulometer which are connected in series. If 27g of Ag is deposited, then the corresponding amount of Cu deposited is   A.    63.6g   B.    31.8g   C.    15.9g   D.    7.95g  
Asked by s.ojaswini17 | 14 Feb, 2019, 08:44: PM
answered-by-expert Expert Answer
According to faradays law, the mass of metal depposited is directly proportional to its equivalent mass so, we can write it as - 
 
E subscript A g end subscript equals space E subscript C u end subscript
 
E subscript A g end subscript equals space fraction numerator 27 over denominator 108 space divided by space 1 end fraction space equals space 1 fourth          { 1 Being the Valency Factor For Ag}
E subscript C u end subscript equals fraction numerator X over denominator 63.5 space divided by space 2 end fraction equals space fraction numerator X over denominator 31.75 end fraction (2 Being the valency Factor for Cu} And [Eqivalent = No of moles ÷ Valency factor]
So, Comparing the above two we get X = 7.9375g. (option d).
Answered by Sumit Chakrapani | 15 Feb, 2019, 02:47: AM

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