CBSE Class 9 Answered
AD
is an altitude of an isosceles triangle ABC in which AB = AC. Show that AD is
also the median of the triangle.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Given: AD is an altitude of an isosceles triangle ABC in which AB = AC
To prove: AD is also the median of the triangle
Proof:
In ABD and ACD,
AB = AC (given)
ADB = ADC (each 90o)
AD = AD (common)
ABD ACD (By SAS)
BD = DC
AD is the median.
Answered by | 04 Jun, 2014, 03:23: PM
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