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ABP and AQP are 2 triangles on same base AP , side AQ and BP intersect at D .C is a point on side AP such that AB is parellel to CD is parallel to PQ .if AB =a ,CD =b,PQ=c.prove that 1/a+1/b=1/c

Asked by mkvinvestments6 16th September 2015, 6:26 PM
Answered by Expert
Answer:

hi doing.

S i n c e space C D vertical line vertical line A B comma space triangle P C D space i s space s i m i l a r space t o space triangle P A B rightwards double arrow b over a equals fraction numerator P C over denominator P A end fraction.. left parenthesis 1 right parenthesis S i m i l a r l y comma space C D vertical line vertical line P Q. space H e n c e comma space triangle A C D space i s space s i m i l a r space t o space triangle A P Q. rightwards double arrow b over c equals fraction numerator A C over denominator P A end fraction.. left parenthesis 2 right parenthesis A d d i n g space left parenthesis 1 right parenthesis space a n d space left parenthesis 2 right parenthesis space w e space g e t b over a plus b over c equals fraction numerator P C over denominator P A end fraction plus fraction numerator A C over denominator P A end fraction rightwards double arrow b open parentheses 1 over a plus 1 over c close parentheses equals fraction numerator P C plus A C over denominator A P end fraction equals fraction numerator P A over denominator A P end fraction equals 1 rightwards double arrow 1 over a plus 1 over c equals 1 over b space left parenthesis P r o v e d right parenthesis

Answered by Expert 16th September 2015, 6:43 PM
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