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CBSE Class 9 Answered

ABCDE is pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) Area ACB = Area ACF (ii) area AEDF = area ABCDE
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

(i) We know, AC||BF

ACF and ACB are triangles between the same parallels and on the same base AC.

Therefore, area ACF = area ACB

(ii) Now, area ACF = area ACB

Add area AEDC on both the sides,

ar AEDC + ar ACF = ar AEDC + ar ACB

area AEDF = area ABCDE

Answered by | 04 Jun, 2014, 03:23: PM

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