CBSE Class 9 Answered
ABCD is a Rhombus. EABF is a straight line such that EA = AB =BF. Prove that ED and FC when produced meet at a right angle.
Asked by kranjay30 | 11 Oct, 2015, 12:29: PM
Expert Answer
Answered by Vimala Ramamurthy | 11 Oct, 2015, 02:24: PM
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