ABCD is a parallelogram whose diagonals AC and BD intersect at O. A line through O intersect AB at P and DC at Q. Prove that:
ar(
POA) = ar(QOC)
Asked by Topperlearning User
10th December 2013,
10:02 AM
Answered by Expert
Answer:
In POA and QOC, we have
AOP = COQ [vertical opp. angle]
AO = OC [diagonals of a ||gm bisect each other]
PAC = QCA [ alt. interior angles]
[ASA criteria]
[congruent figures are equal in areas]
Answered by Expert
10th December 2013,
12:02 PM
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