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CBSE Class 9 Answered

ABCD is a cyclic quad. in which angle BAD = 75 ,angle ABD = 58, angle ADC = 77 , AC and BD  intersect at P.Then find angle DPC ?
Asked by nisha_vini29 | 24 Feb, 2016, 09:29: AM
answered-by-expert Expert Answer
In space Segment space AD angle ACD space equals space angle ABD space space space..... left parenthesis Angles space in space the space same space segment right parenthesis angle ACD space equals space 58 degree............. left parenthesis 1 right parenthesis  ABCD space is space cyclic space quadrilateral angle straight A space plus space angle straight C space equals space 180 degree 75 degree space plus space angle straight C space equals space 180 degree space angle straight C space equals space 105 degree angle ACD space plus space angle ACB space equals space 105 degree 58 degree plus space angle ACB space equals space 105 degree space angle ACB space equals space 47 degree............. left parenthesis 2 right parenthesis  In space Segment space AB angle ADB space equals space angle ACB space space space..... left parenthesis Angles space in space the space same space segment right parenthesis angle ADB space equals space 47 degree  angle straight D space equals space 77 degree angle ADB plus angle BDC space equals space 77 degree space 47 degree plus angle BDC space equals space 77 degree angle BDC space equals space 30 degree............. left parenthesis 3 right parenthesis  In space increment DPC comma angle PDC space plus angle DCP space plus angle DPC space equals space 180 degree 30 degree space plus 58 degree space plus angle DPC space equals space 180 degree........ left square bracket from space left parenthesis 1 right parenthesis space and space left parenthesis 3 right parenthesis right square bracket angle DPC space equals space 92 degree
Answered by Vijaykumar Wani | 24 Feb, 2016, 11:13: AM
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