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CBSE Class 10 Answered

AB is the chord of circle with centre O, BC is the tangent at B As shown in the given figure. Show that PBC= BAP.
Asked by Topperlearning User | 07 Dec, 2013, 07:39: AM
answered-by-expert Expert Answer

ABC=90o, since AB being diameter is perpendicular to tangent BC at the point of contact.

So, ABP + PBC =90o (i)

Also, APB =90o (angle in the semi circle)

So BAP+ABP = 90o (ii)

From (i) and (ii), PBC= BAP

Answered by | 07 Dec, 2013, 09:39: AM

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