AB is the chord of circle with centre O, BC is the tangent at B
As shown in the given figure. Show that PBC= BAP.
ABC=90o, since AB being diameter is perpendicular to tangent BC at the point of contact.
So, ABP + PBC =90o (i)
Also, APB =90o (angle in the semi circle)
So BAP+ABP = 90o (ii)
From (i) and (ii), PBC= BAP
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