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AB is the chord of circle with centre O, BC is the tangent at B

As shown in the given figure. Show that PBC= BAP.

Asked by Topperlearning User 7th December 2013, 7:39 AM
Answered by Expert

ABC=90o, since AB being diameter is perpendicular to tangent BC at the point of contact.

So, ABP + PBC =90o (i)

Also, APB =90o (angle in the semi circle)

So BAP+ABP = 90o (ii)

From (i) and (ii), PBC= BAP

Answered by Expert 7th December 2013, 9:39 AM
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