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AB is a diameter of a circle. BC is the tangent at B as shown in the given figure. Show that PBC = BAP.

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert

ABC=90o Since AB being diameter is perpendicular to tangent BC at the point of contact.

So ABP +PBC =90o (i)

Also APB =90o (angle in the semi-circle)

So BAP+ABP = 90o (ii) (using angle sum property of triangles)

From (i) and (ii),


Answered by Expert 4th June 2014, 3:23 PM
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