Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

AB is a diameter of a circle. BC is the tangent at B as shown in the given figure. Show that PBC = BAP.

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

ABC=90o Since AB being diameter is perpendicular to tangent BC at the point of contact.

So ABP +PBC =90o (i)

Also APB =90o (angle in the semi-circle)

So BAP+ABP = 90o (ii) (using angle sum property of triangles)

From (i) and (ii),

PBC = BAP

Answered by Expert 4th June 2014, 3:23 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp