Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

AB is a diameter of a circle. BC is the tangent at B as shown in the given figure. Show that PBC = BAP.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

ABC=90o Since AB being diameter is perpendicular to tangent BC at the point of contact.

So ABP +PBC =90o (i)

Also APB =90o (angle in the semi-circle)

So BAP+ABP = 90o (ii) (using angle sum property of triangles)

From (i) and (ii),

PBC = BAP

Answered by | 04 Jun, 2014, 03:23: PM
CBSE 10 - Maths
Asked by amikasangma080 | 11 Oct, 2021, 06:14: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by muskanmahek2411 | 08 Oct, 2021, 10:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by anishasheoran372 | 13 Jul, 2021, 09:33: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by anjalirajp004 | 22 Sep, 2020, 08:17: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by rashikediadelhi | 21 Sep, 2020, 09:02: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by prasutally | 26 May, 2019, 08:22: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×