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CBSE Class 9 Answered

A wooden toy is in the form of a cone Surmounted on a hemisphere. The diameter of the base of the cone is 6 cm and its height is 4 cm. Find the cost of painting the toy at the rate of Rs. 5 per 1000 cm2
Asked by dimplesharma0810 | 03 Mar, 2016, 01:04: PM
answered-by-expert Expert Answer
 
begin mathsize 12px style R a d i u s space o f space b a s e space o f space c o n e equals r equals 3 space c m H e i g h t space o f space c o n e space equals space h space equals space 4 space c m L e t space l space b e space t h e space s l a n t space h e i g h t space o f space t h e space c o n e. T h e n comma space l equals square root of h squared plus r squared end root equals square root of 4 squared plus 3 squared end root equals square root of 25 equals 5 space c m L S A space o f space c o n e equals πrl equals 22 over 7 cross times 3 cross times 5 equals 330 over 7 cm squared SA thin space of space hemisphere equals 2 πr squared equals 2 cross times 22 over 7 cross times 3 cross times 3 equals 396 over 7 cm squared rightwards double arrow TSA space of space the space toy equals open parentheses 330 over 7 plus 396 over 7 close parentheses equals 103.71 space cm squared Rate space of space painting space the space toy equals Rs. space 5 space per space 1000 space cm squared equals Rs. space 5 over 1000 divided by cm squared rightwards double arrow Cost space of space painting space the space toy equals open parentheses 103.71 cross times 5 over 1000 close parentheses equals Re. space 0.52 equals 52 space paise space end style
Answered by Rashmi Khot | 03 Mar, 2016, 02:43: PM

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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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CBSE 9 - Maths
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