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A weight W is tied to two strings passing over the frictionless pulleys A and B as shown in the fig. If weights P and Q move downwards with speed V, the weight W at any instant rises with the speed-
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Asked by Sridevi | 19 Sep, 2019, 11:07: PM
answered-by-expert Expert Answer
In figure we see that , length of strings from point o to pulleys and inter distance between pulleys are related as
 
h2 + d2 = l2  ......................(1)
 
By differentiating with respect to time, eqn.(1), we get,  2h (dh/dt) = 2l (dl/dt)  ...............(1)
 
since (dl/dt) = v  , we get  dh/dt = (l/h) v  = v/cosθ
 
Hence the block W raises with speed at any instant = v/cosθ 
Answered by Thiyagarajan K | 20 Sep, 2019, 10:49: AM

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