Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

A  wedg ewith mass M rests on a frictionless horizontal tabletop . A block with mass m is placed on the wedge There is no friction between the block and the wedge the system is released from rest . calculate the acceleration of the wedge.
Asked by Srishti Ananya | 14 Jul, 2019, 11:29: AM
answered-by-expert Expert Answer
Since centre of mass is not moving, acceleration of centre of mass is zero.
 
If am is acceleration of block of mass m and aM is acceleration of wedge of mass M,
 
then we have ,     m × a+ M × aM  = 0 
 
hence we get,     aM =  -(m/M) × am = -(m/M)×gsinθ
 
where g is acceleration due to gravity and θ is angle of wedge as shown in figure
Answered by Thiyagarajan K | 14 Jul, 2019, 05:11: PM
CBSE 12-science - Physics
Asked by dasrituparna1999 | 13 Apr, 2024, 06:56: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mishrigupta19319 | 08 Apr, 2024, 06:28: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by madhav9119887644 | 07 Apr, 2024, 08:10: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mishrigupta19319 | 07 Apr, 2024, 11:23: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by adityagalar2007 | 06 Apr, 2024, 01:06: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by amlanmcob | 06 Apr, 2024, 12:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by manishamunda787 | 02 Apr, 2024, 11:07: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×