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CBSE Class 10 Answered

a vessel is in the form of an inverted cone its height is8cm and radius of top which is open is 5cm . it is filled up with water up to brim when lead short each of which is the sphere of radius 0.5 cm are dropped into the vessal 1/4th of water flows out. find the no of lead short droped in vessal.
Asked by vikramjsingh53 | 14 Dec, 2018, 05:33: PM
answered-by-expert Expert Answer
Volume of water = (1/3)π×5×5×8 = (200/3)π cm3 

(1/4)th of volume of water = volume of total number of lead shorts.

let N be the number of lead shorts
 
Then we have,  (1/4)×(200/3)π = N×(4/3)π×(1/2)×(1/2)×(1/2)
 
after simplification of the above equation, we get N = 100
Answered by Thiyagarajan K | 15 Dec, 2018, 07:19: AM

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