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A vessel contains oil  (density 0.8 g/cc) over mercury  (density 13.6 g/cc ). A homogeneous sphere floats with half its  volume immersed in mercury and other half in oil . The density of the material is ?  
Asked by jmorakhia | 24 Apr, 2019, 07:11: PM
answered-by-expert Expert Answer
when a homogeneous solid sphere floats in oil over mercury, such that half volume in mercury and other half in oil,
 
then we have,  V×ρs×g = (V/2)×ρm×g + (V/2)×ρo×g  ...................(1)
 
where V is volume of sphere, ρs , ρm and ρo are densities of sphere, mercury and oil respectively.
 
eqn.(1) is simplified as, ρs = ( ρm/2 ) + ( ρo /2)  =  (13.6+0.8)/2 = 7.2 g/cc
 
Answered by Thiyagarajan K | 24 Apr, 2019, 07:56: PM

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