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a unit cell consits of a cube in which anions B are present at each corner and cations A at the centre of the center of the alternate faces of the unit cell .what is the simplest formula  of the compound ?

Asked by vasturushi 18th July 2017, 12:58 PM
Answered by Expert
Answer:
FCC - 
Contribution of an atom placed at corner of the unit cell is 1/8.
Therefore, the total no. of anion (B) which are present in a unit cell is = 1/8 × total no. of corners = 1/8 × 8 = 1 anion
Contribution of an atom placed at face centre = 1/2
When cations are placed at the alternative faces, the otal no. of face centred atoms are 2 as shown below in:
So, total no. of cations are = 1/2 × 2 = 1
Thus, the formula of compound is AB.
Answered by Expert 18th July 2017, 6:54 PM
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