A uniform rod of mass 6M and length 6l is bent to make an equilateral hexagon.Its M.I about an axis passing through the centre of mass and perpendicular to the plane of hexagon is
Asked by m.nilu
18th October 2018,
10:36 PM
Answered by Expert
Answer:
Given rod of length 6l is made as a hexagon of side l as shown in figure. Each side has a mass M.
Moment of inertia about the axis passing through middle of a rod of length l is M×(l2/12).
M is mass of rod.
Hence moment of inertia of side AB of a hexagon, by parallel axis theorem = M×(l2/12) + M×(3/4)×l2 = M×(5/6)×l2
Hence moment of inertia of all six sides = 5×M×l2
Answered by Expert
19th October 2018,
5:21 AM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer 1/10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Thermodynamics
- 2 Gravitation
- 3 Electromagnetic Waves
- 4 Communication Systems
- 5 Laws of Motion
- 6 Current Electricity
- 7 Work, Energy and Power
- 8 Kinematics
- 9 Physics and Measurement
- 10 Rotational Motion
- 11 Properties of Solids and Liquids
- 12 Kinetic Theory of Gases
- 13 Oscillations and Waves
- 14 Electrostatics
- 15 Magnetic Effects of Current and Magnetism
- 16 Electromagnetic Induction and Alternating Currents
- 17 Optics
- 18 Dual Nature of Matter and Radiation
- 19 Atoms and Nuclei
- 20 Electronic Devices
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
