Contact

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (North)

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

8788563422

Mon to Sat - 10 AM to 7 PM

# A uniform rod of mass 6M and length 6l is bent to make an equilateral hexagon.Its M.I about an axis passing through the centre of mass and perpendicular to the plane of hexagon is

Asked by m.nilu 18th October 2018, 10:36 PM
Given rod of length 6l is made as a hexagon of side l as shown in figure. Each side has a mass M.
Moment of inertia about the axis passing through middle of a rod of length l is M×(l2/12).
M is mass of rod.

Hence moment of inertia of side AB of a hexagon, by parallel axis theorem = M×(l2/12) + M×(3/4)×l2 = M×(5/6)×l2
Hence moment of inertia of all six sides = 5×M×l2

Answered by Expert 19th October 2018, 5:21 AM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer 1/10

### Free related questions

27th January 2019, 10:10 PM
27th January 2019, 1:33 PM
22nd February 2019, 10:43 PM
RELATED STUDY RESOURCES :