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ICSE Class 10 Answered

A uniform meter rule is pivoted at its mid - point. A weight of 50gf is suspended at one end of it. Where should a weight of 100gf be suspended to keep the rule horizontal ? 
Asked by pratyakshajha.12 | 31 Mar, 2015, 08:13: PM
answered-by-expert Expert Answer
begin mathsize 12px style Let space straight L space be space the space uniform space length space space of space meter space rule moment space of space the space weight space at space one space end space straight W subscript 1 space equals space 40 space cross times space straight L over 2 Let space straight x space be space the space distance space from space mid space point space where space 100 space gf space weight space is space placed therefore space moment space of space the space weight space straight W subscript 2 space equals space 100 space cross times space straight x For space the space rotational space equilibrium space we space have comma straight W subscript 1 space equals space straight W subscript 2 50 space cross times space straight L over 2 space equals space 100 space straight x straight x space equals space straight L over 4 space end style
Answered by Priyanka Kumbhar | 02 Apr, 2015, 09:36: AM

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