NEET Class neet Answered
A tungsten wire, 0.5 mm in diameter, is just stretched between two fixed points at a temperature of 40°C. Determine the tension in the wire when the temperature falls to 20°C. (coefficient of linear expansion of tungsten = 4.5 × 10–6/°C ; Young's modulus of tungsten = 3.45 × 1010 Nm–2)
Asked by jyothiboda22 | 26 Aug, 2019, 09:35: PM
Expert Answer
Youngs modulus Y = Stress / Strain = ( T / A ) / ( Δl / l ) ........................... (1)
where T is tension in wire, A is area of cross section, Δl is change in length due to fall in temperature
and l is its original length .
Hence Tension T = Y × ( Δl / l ) × A ......................... (2)
change in length of wire = Δl = l × α × ΔT
Hence eqn.(2) is rewritten as, T = Y × α × ΔT × A
T = 3.45 × 1010 × 4.5 × 10-6 ×20 × (π×0.5×0.5×10-6)/4 ≈ 0.61 N
Answered by Thiyagarajan K | 26 Aug, 2019, 10:15: PM
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