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a truck of mass 5000kg traveling at 40m/s is brought to rest by applying its brakes. the truck comes to rest after traveling 20m after application of brakes. what is the kinetic energy of the truck?

Asked by 28th December 2011, 12:00 AM
Answered by Expert
Answer:

Here v=0 m/s and u= 40m/s

S= 20 m

V2-u2= 2as

-(20)2 =2x20a

-400/40=a

-10m/s2= a

K.E= m v2

=1/2x 5000x40 x40                 =                      5000x20x40               = 4x 106J

Answered by Expert 29th December 2011, 12:49 PM
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