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CBSE Class 11-science Answered

A thin circular ring of radius r has a positive charge. If a negative charge q is placed at a small distance x from the centre. Then find the time period of oscillation of the particle
Asked by arushidabhade | 26 Apr, 2020, 11:52: PM
answered-by-expert Expert Answer
L e t space t h e space c h a r g e space o f space t h e space r i n g space b e space Q
F subscript n e t end subscript equals E left parenthesis negative q right parenthesis
F subscript n e t end subscript equals fraction numerator K Q x over denominator open parentheses r squared plus x squared close parentheses to the power of begin display style 3 over 2 end style end exponent end fraction left parenthesis negative q right parenthesis
A s space x less than less than less than r
F subscript n e t end subscript equals fraction numerator K Q x over denominator r cubed end fraction left parenthesis negative q right parenthesis minus negative negative negative negative negative negative left parenthesis 1 right parenthesis
N o w space a s space p e r space t h e space l a w s space o f space S H M
F subscript n e t end subscript equals negative m omega squared x minus negative negative negative negative negative left parenthesis 2 right parenthesis
E q u a t i n g space 1 space a n d space 2 w e space g e t
fraction numerator K Q x over denominator r cubed end fraction left parenthesis negative q right parenthesis equals negative m omega squared x

omega equals square root of fraction numerator K Q q over denominator m r cubed end fraction end root
T equals 2 straight pi square root of mr cubed over KQq end root
Answered by Utkarsh Lokhande | 28 Apr, 2020, 01:02: AM
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