ICSE Class 9 Answered
A test tube loaded with lead shots floats to the mark X in water. The test-tube along with lead shots weighs 25 g. When the test-tube is floated in brine, 5 g of lead shots were added to make it float upto level X. Find the relative density of brine.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
While floating in water, the weight of the floating test tube = 25 gf. This will be equal to the weight of the water displaced by the floating test-tube, immersed to the mark X.
While floating in brine, the weight of the floating test-tube = 25 + 5 = 30 gf. Since the test-tube remains immersed to the same mark X, while floating in brine.
Therefore, 30gf is the weight of the same volume of brine.
Since R.D =
Therefore, R.D of brine = 1.2
Answered by | 04 Jun, 2014, 03:23: PM