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a student is able to throw a ball vertically to maximum height 40 m.The maximum distance to which the student can throw the ball in the horizontal direction?

Asked by yogipapa1999 2nd July 2018, 10:19 AM
Answered by Expert
Answer:
From the given maximum vertical distance h = 40 m,
initial speed is calculated using "v2 = u2 - 2 g h " , assuming final speed v = 0 . 
 
initial speed, u = begin mathsize 12px style square root of 2 space g space h end root space equals space square root of 2 cross times 9.8 cross times 40 space end root space equals space 28 space m divided by s end style
Horizontal direction, maximum range is obtained when the projection angle with horizontal is 45º.
 
Range for projectile motion, R = (u2×sin2α) / g  , if α = 45º, R = (28×28)/9.8 = 80 m 
Answered by Expert 2nd July 2018, 10:57 AM
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