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# a student is able to throw a ball vertically to maximum height 40 m.The maximum distance to which the student can throw the ball in the horizontal direction?

Asked by yogipapa1999 2nd July 2018, 10:19 AM
From the given maximum vertical distance h = 40 m,
initial speed is calculated using "v2 = u2 - 2 g h " , assuming final speed v = 0 .

initial speed, u =
Horizontal direction, maximum range is obtained when the projection angle with horizontal is 45º.

Range for projectile motion, R = (u2×sin2α) / g  , if α = 45º, R = (28×28)/9.8 = 80 m
Answered by Expert 2nd July 2018, 10:57 AM
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